What is the answer to (2z-1)/3+1=(3z-1)/3 ?

The answer to (2z-1)/3+1=(3z-1)/3 is z=3

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(2z-1)/3+1=(3z-1)/3

\frac{2 z - 1}{3} + 1 = \frac{3 z - 1}{3}

z = 3

Solution steps

\frac{2 z - 1}{3} + 1 = \frac{3 z - 1}{3}

Multiply both sides by

3

2 z + 2 = 3 z - 1

Move

2

to the right side

2 z = 3 z - 3

Move

3 z

to the left side

- z = - 3

Divide both sides by

- 1

z = 3

x, 2 x - 3 y - 7 = 0

y, x - 4 y = 1

V^{1} i = \frac{( 0.18 - 0 )}{( 15925 - 0 )}

- 12 x + 60 = 48

8 x + 2 = 18

What is the answer to (2z-1)/3+1=(3z-1)/3 ?
The answer to (2z-1)/3+1=(3z-1)/3 is z=3
Solve for z: (2z-1)/3+1=(3z-1)/3
The solution is z=3