What is the answer to log_{10}(2)(x-5)+log_{10}(2)(x+2)=3 ?

The answer to log_{10}(2)(x-5)+log_{10}(2)(x+2)=3 is x=(3+3log_{10}(2))/(2log_{10)(2)}

Solve for x: log_{10}(2)(x-5)+log_{10}(2)(x+2)=3

The solution is x=(3+3log_{10}(2))/(2log_{10)(2)}

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lo g_{10} (2) (x - 5) + lo g_{10} (2) (x + 2) = 3

x = \frac{3 + 3 lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

Solution steps

lo g_{10} (2) (x - 5) + lo g_{10} (2) (x + 2) = 3

Expand

lo g_{10} (2) (x - 5) + lo g_{10} (2) (x + 2) : 2 lo g_{10} (2) x - 3 lo g_{10} (2)

2 lo g_{10} (2) x - 3 lo g_{10} (2) = 3

Move

3 lo g_{10} (2)

to the right side

2 lo g_{10} (2) x = 3 + 3 lo g_{10} (2)

Divide both sides by

2 lo g_{10} (2)

x = \frac{3 + 3 lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

- 2 (3 p - 5) = 10

2 (3 v - 6) = 12

x, 4 y + 3 x = 4

1.5 x - 0.7 = 0.6 (3 - 5 x)

x, \frac{2}{3} x - 3 y = 7

What is the answer to log_{10}(2)(x-5)+log_{10}(2)(x+2)=3 ?
The answer to log_{10}(2)(x-5)+log_{10}(2)(x+2)=3 is x=(3+3log_{10}(2))/(2log_{10)(2)}
Solve for x: log_{10}(2)(x-5)+log_{10}(2)(x+2)=3
The solution is x=(3+3log_{10}(2))/(2log_{10)(2)}