What are the solutions to the equation x^2-56=x ?

The solutions to the equation x^2-56=x are x=8,x=-7

Find the zeros of x^2-56=x

The zeros of x^2-56=x are x=8,x=-7

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x^{2} - 56 = x

x = 8, x = - 7

Solution steps

x^{2} - 56 = x

Move

x

to the left side

x^{2} - 56 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 56) = 15

x_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 1}

x = \frac{- ( - 1 ) + 15}{2 \cdot 1} : 8

x = \frac{- ( - 1 ) - 15}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 8, x = - 7

4 x^{2} + 36 x + 80

\frac{5 ^{3}}{5 ^{5}}

84 - 8 f = 580

\frac{30}{2}

\frac{6 x - 2}{x + 1} \leq 5

What are the solutions to the equation x^2-56=x ?
The solutions to the equation x^2-56=x are x=8,x=-7
Find the zeros of x^2-56=x
The zeros of x^2-56=x are x=8,x=-7