What is the answer to log_{10}(2)(2x+1)=4 ?

The answer to log_{10}(2)(2x+1)=4 is x=(4-log_{10}(2))/(2log_{10)(2)}

Solve for x: log_{10}(2)(2x+1)=4

The solution is x=(4-log_{10}(2))/(2log_{10)(2)}

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lo g_{10} (2) (2 x + 1) = 4

x = \frac{4 - lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

Solution steps

lo g_{10} (2) (2 x + 1) = 4

Divide both sides by

lo g_{10} (2)

2 x + 1 = \frac{4}{lo g _{10} ( 2 )}

Move

1

to the right side

2 x = \frac{4}{lo g _{10} ( 2 )} - 1

Divide both sides by

2

x = \frac{4 - lo g _{10} ( 2 )}{2 lo g _{10} ( 2 )}

12 x - 3 x = 31 + 5

(x + 7) 2 = 49

\frac{27 + d}{4} = 3 + d

4 x + x = 45

r, q = r + s - t

What is the answer to log_{10}(2)(2x+1)=4 ?
The answer to log_{10}(2)(2x+1)=4 is x=(4-log_{10}(2))/(2log_{10)(2)}
Solve for x: log_{10}(2)(2x+1)=4
The solution is x=(4-log_{10}(2))/(2log_{10)(2)}