What are the solutions to the equation -2x+x^2=-2 ?

The solutions to the equation -2x+x^2=-2 are x=1+i,x=1-i

Find the zeros of -2x+x^2=-2

The zeros of -2x+x^2=-2 are x=1+i,x=1-i

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- 2 x + x^{2} = - 2

x = 1 + i, x = 1 - i

Solution steps

- 2 x + x^{2} = - 2

Move

2

to the left side

- 2 x + x^{2} + 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

x = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

x = 1 + i, x = 1 - i

3 x - 4 = 2 x + 0.7

9 x^{2} y + 6 x y - 12 x

2 x (x - 3) = x - 3

x^{2} - 4 x + 4 = 1

What are the solutions to the equation -2x+x^2=-2 ?
The solutions to the equation -2x+x^2=-2 are x=1+i,x=1-i
Find the zeros of -2x+x^2=-2
The zeros of -2x+x^2=-2 are x=1+i,x=1-i