What is the answer to (x-1)log_{10}(2)+log_{10}(8)=log_{10}(4) ?

The answer to (x-1)log_{10}(2)+log_{10}(8)=log_{10}(4) is x=0

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(x-1)log_{10}(2)+log_{10}(8)=log_{10}(4)

(x - 1) lo g_{10} (2) + lo g_{10} (8) = lo g_{10} (4)

x = 0

Solution steps

(x - 1) lo g_{10} (2) + lo g_{10} (8) = lo g_{10} (4)

Move

lo g_{10} (8)

to the right side

(x - 1) lo g_{10} (2) = - lo g_{10} (2)

Divide both sides by

lo g_{10} (2)

x - 1 = - 1

Move

1

to the right side

x = 0

x, 5 x - y - 6 = 0

\frac{x}{- 5} = 3

x, 8 x - 9 y = 72

\frac{9}{12} = \frac{x}{16}

y, \frac{14 + 3 y - 4 z}{2} + \frac{2 ( z - 1 )}{3} - z = 0

What is the answer to (x-1)log_{10}(2)+log_{10}(8)=log_{10}(4) ?
The answer to (x-1)log_{10}(2)+log_{10}(8)=log_{10}(4) is x=0
Solve for x: (x-1)log_{10}(2)+log_{10}(8)=log_{10}(4)
The solution is x=0