What is the answer to solvefor h,s=2pirh+2pir^2 ?

The answer to solvefor h,s=2pirh+2pir^2 is h=(s-2pir^2)/(2pir);\quad r\ne 0

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solvefor h,s=2pirh+2pir^2

solve for

h, s = 2 π r h + 2 π r^{2}

h = \frac{s - 2 π r ^{2}}{2 π r}; r \neq = 0

Solution steps

s = 2 π r h + 2 π r^{2}

Switch sides

2 π r h + 2 π r^{2} = s

Move

2 π r^{2}

to the right side

2 π r h = s - 2 π r^{2}

Divide both sides by

2 π r; r \neq = 0

h = \frac{s - 2 π r ^{2}}{2 π r}; r \neq = 0

\frac{x + 5}{4} - \frac{1}{2} = \frac{x + 1}{8}

\frac{49}{56} = \frac{z}{8}

- 5 (r + 4) = - 59

\frac{x + a}{a} - \frac{a ^{2} + b ^{2}}{ab} = 2 + \frac{x + b}{b}

6 x + 25 = 73

What is the answer to solvefor h,s=2pirh+2pir^2 ?
The answer to solvefor h,s=2pirh+2pir^2 is h=(s-2pir^2)/(2pir);\quad r\ne 0