What are the solutions to the equation 5s^2-45s=0 ?

The solutions to the equation 5s^2-45s=0 are s=9,s=0

Find the zeros of 5s^2-45s=0

The zeros of 5s^2-45s=0 are s=9,s=0

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5 s^{2} - 45 s = 0

s = 9, s = 0

Solution steps

5 s^{2} - 45 s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 45 ) \pm ( - 45 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 45)^{2} - 4 \cdot 5 \cdot 0 = 45

s_{1, 2} = \frac{- ( - 45 ) \pm 45}{2 \cdot 5}

Separate the solutions

s_{1} = \frac{- ( - 45 ) + 45}{2 \cdot 5}, s_{2} = \frac{- ( - 45 ) - 45}{2 \cdot 5}

s = \frac{- ( - 45 ) + 45}{2 \cdot 5} : 9

s = \frac{- ( - 45 ) - 45}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

s = 9, s = 0

2 b c + 2 b + 1 + c

∣ 1 - 2 x ∣ + ∣ 5 x - 4 ∣ = 5

\frac{5}{\frac{4}{2}}

7 + 3 x - 2 = 11

(\frac{2}{15} + y) - \frac{7}{30} = \frac{1}{10}

What are the solutions to the equation 5s^2-45s=0 ?
The solutions to the equation 5s^2-45s=0 are s=9,s=0
Find the zeros of 5s^2-45s=0
The zeros of 5s^2-45s=0 are s=9,s=0