What is the answer to solvefor A,2x^2+3=A(x-1)^2+Bx(x-1)+Cx ?

The answer to solvefor A,2x^2+3=A(x-1)^2+Bx(x-1)+Cx is A=(2x^2+3-Bx(x-1)-xC)/((-1+x)^2);\quad x\ne 1

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solvefor A,2x^2+3=A(x-1)^2+Bx(x-1)+Cx

solve for

A, 2 x^{2} + 3 = A (x - 1)^{2} + B x (x - 1) + C x

A = \frac{2 x ^{2} + 3 - B x ( x - 1 ) - x C}{( - 1 + x ) ^{2}}; x \neq = 1

Solution steps

2 x^{2} + 3 = A (x - 1)^{2} + B x (x - 1) + C x

Switch sides

A (x - 1)^{2} + B x (x - 1) + C x = 2 x^{2} + 3

Move

B x (x - 1)

to the right side

A (x - 1)^{2} + C x = 2 x^{2} + 3 - B x (x - 1)

Move

C x

to the right side

A (x - 1)^{2} = 2 x^{2} + 3 - B x (x - 1) - C x

Divide both sides by

(x - 1)^{2}; x \neq = 1

A = \frac{2 x ^{2} + 3 - B x ( x - 1 ) - x C}{( - 1 + x ) ^{2}}; x \neq = 1

n, l = \frac{125}{m} + 50 n

5 (x - 4) - 10 = 10

f, f = \frac{x y ^{2}}{x ^{2} - y ^{2}}

8 q + 5 = 21

y, yz - 1 = \frac{3}{x} - x y

What is the answer to solvefor A,2x^2+3=A(x-1)^2+Bx(x-1)+Cx ?
The answer to solvefor A,2x^2+3=A(x-1)^2+Bx(x-1)+Cx is A=(2x^2+3-Bx(x-1)-xC)/((-1+x)^2);\quad x\ne 1