What are the solutions to the equation 3x^2-2x-6=0 ?

The solutions to the equation 3x^2-2x-6=0 are x=(1+sqrt(19))/3 ,x=(1-sqrt(19))/3

Find the zeros of 3x^2-2x-6=0

The zeros of 3x^2-2x-6=0 are x=(1+sqrt(19))/3 ,x=(1-sqrt(19))/3

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3 x^{2} - 2 x - 6 = 0

x = \frac{1 + 19}{3}, x = \frac{1 - 19}{3}

Decimal Notation

x = 1.78629 \dots, x = - 1.11963 \dots

Solution steps

3 x^{2} - 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 6) = 219

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 19}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 19}{2 \cdot 3} : \frac{1 + 19}{3}

x = \frac{- ( - 2 ) - 2 19}{2 \cdot 3} : \frac{1 - 19}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 19}{3}, x = \frac{1 - 19}{3}

i^{62}

\frac{2 r + 8}{4} = \frac{3 r - 9}{3}

lo g_{9} (\frac{1}{81}) = - 2

- 48 + 4 ∣ 9 - x ∣ \geq - 36

What are the solutions to the equation 3x^2-2x-6=0 ?
The solutions to the equation 3x^2-2x-6=0 are x=(1+sqrt(19))/3 ,x=(1-sqrt(19))/3
Find the zeros of 3x^2-2x-6=0
The zeros of 3x^2-2x-6=0 are x=(1+sqrt(19))/3 ,x=(1-sqrt(19))/3