What is the answer to (z+4)/5+(1-z)/4 = 15/10 ?

The answer to (z+4)/5+(1-z)/4 = 15/10 is z=-9

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(z+4)/5+(1-z)/4 = 15/10

\frac{z + 4}{5} + \frac{1 - z}{4} = \frac{15}{10}

z = - 9

Solution steps

\frac{z + 4}{5} + \frac{1 - z}{4} = \frac{15}{10}

Cancel the common factor:

5

\frac{z + 4}{5} + \frac{1 - z}{4} = \frac{3}{2}

Multiply by LCM

4 (z + 4) + 5 (- z + 1) = 30

Expand

4 (z + 4) + 5 (- z + 1) : - z + 21

- z + 21 = 30

Move

21

to the right side

- z = 9

Divide both sides by

- 1

z = - 9

\frac{2}{3} x = 18

\frac{7 x + 4}{3} = 2 x - 1

y = - 2 (0)^{2}

5 t + 20 = 19 t + 6

x, - 10 x + 5 y = 20

What is the answer to (z+4)/5+(1-z)/4 = 15/10 ?
The answer to (z+4)/5+(1-z)/4 = 15/10 is z=-9
Solve for z: (z+4)/5+(1-z)/4 = 15/10
The solution is z=-9