What is the answer to solvefor x,(y-4)2=-8(x+1) ?

The answer to solvefor x,(y-4)2=-8(x+1) is x=-(y-4)/4-1

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solvefor x,(y-4)2=-8(x+1)

solve for

x, (y - 4) 2 = - 8 (x + 1)

x = - \frac{y - 4}{4} - 1

Solution steps

(y - 4) \cdot 2 = - 8 (x + 1)

Switch sides

- 8 (x + 1) = (y - 4) \cdot 2

Divide both sides by

- 8

x + 1 = - \frac{y - 4}{4}

Move

1

to the right side

x = - \frac{y - 4}{4} - 1

5 z - 9 = 4 z - 2

x, 5 y = - 2 x - 4

7 (x - 2) = 21

x, y + 1 = - 3 (x + 2)

3 (7 - 4 x) - 1 = 4 (6 - 2 x) + 3 x

What is the answer to solvefor x,(y-4)2=-8(x+1) ?
The answer to solvefor x,(y-4)2=-8(x+1) is x=-(y-4)/4-1