What is the answer to (2t-5)/5+2=(t-2)/3+2 ?

The answer to (2t-5)/5+2=(t-2)/3+2 is t=5

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(2t-5)/5+2=(t-2)/3+2

\frac{2 t - 5}{5} + 2 = \frac{t - 2}{3} + 2

t = 5

Solution steps

\frac{2 t - 5}{5} + 2 = \frac{t - 2}{3} + 2

Subtract

2

from both sides

\frac{2 t - 5}{5} + 2 - 2 = \frac{t - 2}{3} + 2 - 2

Simplify

\frac{2 t - 5}{5} = \frac{t - 2}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 t - 5) \cdot 3 = 5 (t - 2)

Expand

(2 t - 5) \cdot 3 : 6 t - 15

Expand

5 (t - 2) : 5 t - 10

6 t - 15 = 5 t - 10

Move

15

to the right side

6 t = 5 t + 5

Move

5 t

to the left side

t = 5

- 2 x + \frac{1}{4} = \frac{2}{5} - x

\frac{5}{6} + \frac{1}{4} x = \frac{1}{6}

3 (x + 2) = 2 (x - 7)

\frac{b + 4}{5} = \frac{7}{4}

3 \frac{x}{4} - \frac{1}{3} = 1 - \frac{2}{3} (x - \frac{1}{6})

What is the answer to (2t-5)/5+2=(t-2)/3+2 ?
The answer to (2t-5)/5+2=(t-2)/3+2 is t=5
Solve for t: (2t-5)/5+2=(t-2)/3+2
The solution is t=5