What is the answer to (5x-7)(2x+1)-10x(x-4)=0 ?

The answer to (5x-7)(2x+1)-10x(x-4)=0 is x= 7/31

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(5x-7)(2x+1)-10x(x-4)=0

(5 x - 7) (2 x + 1) - 10 x (x - 4) = 0

x = \frac{7}{31}

Decimal Notation

x = 0.22580 \dots

Solution steps

(5 x - 7) (2 x + 1) - 10 x (x - 4) = 0

Expand

(5 x - 7) (2 x + 1) - 10 x (x - 4) : 31 x - 7

31 x - 7 = 0

Move

7

to the right side

31 x = 7

Divide both sides by

31

x = \frac{7}{31}

n + 8 = 22

x, 18 x - 15 y = - 315

5 p - 11 = 13 p - 43

lo g_{2} (32) = x + 2

7 (x - 2) + 3 = 4 (2 x - 6) - 2

What is the answer to (5x-7)(2x+1)-10x(x-4)=0 ?
The answer to (5x-7)(2x+1)-10x(x-4)=0 is x= 7/31
Solve for x: (5x-7)(2x+1)-10x(x-4)=0
The solution is x= 7/31