What is the answer to solvefor x,3y^2x-2x+5=1 ?

The answer to solvefor x,3y^2x-2x+5=1 is x=-4/(3y^2-2);\quad y\ne sqrt(2/3),y\ne-sqrt(2/3)

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solvefor x,3y^2x-2x+5=1

solve for

x, 3 y^{2} x - 2 x + 5 = 1

x = - \frac{4}{3 y ^{2} - 2}; y \neq = \frac{2}{3}, y \neq = - \frac{2}{3}

Solution steps

3 y^{2} x - 2 x + 5 = 1

Move

5

to the right side

3 y^{2} x - 2 x = - 4

Factor

3 y^{2} x - 2 x : x (3 y^{2} - 2)

x (3 y^{2} - 2) = - 4

Divide both sides by

3 y^{2} - 2; y \neq = \frac{2}{3}, y \neq = - \frac{2}{3}

x = - \frac{4}{3 y ^{2} - 2}; y \neq = \frac{2}{3}, y \neq = - \frac{2}{3}

6 x = 14

y = 3 (- 1) + 4

\frac{3 x}{4} = 21

\frac{3 x}{4} = 12

F, C = \frac{5 ( F - 32 )}{9}

What is the answer to solvefor x,3y^2x-2x+5=1 ?
The answer to solvefor x,3y^2x-2x+5=1 is x=-4/(3y^2-2);\quad y\ne sqrt(2/3),y\ne-sqrt(2/3)