What are the solutions to the equation x^2-15x=-50 ?

The solutions to the equation x^2-15x=-50 are x=10,x=5

Find the zeros of x^2-15x=-50

The zeros of x^2-15x=-50 are x=10,x=5

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x^{2} - 15 x = - 50

x = 10, x = 5

Solution steps

x^{2} - 15 x = - 50

Move

50

to the left side

x^{2} - 15 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 50 = 5

x_{1, 2} = \frac{- ( - 15 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 5}{2 \cdot 1}

x = \frac{- ( - 15 ) + 5}{2 \cdot 1} : 10

x = \frac{- ( - 15 ) - 5}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 10, x = 5

2 x^{2} + 12 x - 32 = 0

19 k = \frac{19 \cdot 9}{100 \cdot 10}

x^{2} \leq 6 x

∣ 1 - 2 x ∣ > 3

\frac{1}{x - 1} - \frac{2}{x} > 0

What are the solutions to the equation x^2-15x=-50 ?
The solutions to the equation x^2-15x=-50 are x=10,x=5
Find the zeros of x^2-15x=-50
The zeros of x^2-15x=-50 are x=10,x=5