What is the answer to 3(X+2)(2X-5)=(2X)(3X-2)-29 ?

The answer to 3(X+2)(2X-5)=(2X)(3X-2)-29 is X=1

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3(X+2)(2X-5)=(2X)(3X-2)-29

3 (X + 2) (2 X - 5) = (2 X) (3 X - 2) - 29

X = 1

Solution steps

3 (X + 2) (2 X - 5) = (2 X) (3 X - 2) - 29

3 (X + 2) (2 X - 5) = 2 X (3 X - 2) - 29

Expand

(X + 2) (2 X - 5) : 2 X^{2} - X - 10

3 (2 X^{2} - X - 10) = 2 X (3 X - 2) - 29

Expand

3 (2 X^{2} - X - 10) : 6 X^{2} - 3 X - 30

6 X^{2} - 3 X - 30 = 2 X (3 X - 2) - 29

Expand

2 X (3 X - 2) : 6 X^{2} - 4 X

6 X^{2} - 3 X - 30 = 6 X^{2} - 4 X - 29

Move

30

to the right side

6 X^{2} - 3 X = 6 X^{2} - 4 X + 1

Subtract

6 X^{2} - 4 X

from both sides

6 X^{2} - 3 X - (6 X^{2} - 4 X) = 6 X^{2} - 4 X + 1 - (6 X^{2} - 4 X)

Simplify

X = 1

b, f b + 3 b = d

0.2 x + 2 = - 1.5 (3.2 x - 7) + 7

y, y - 5 = x

2 (x + 9) - 15 = - 3

x, y + 2 = \frac{5}{3} (x + 6)

What is the answer to 3(X+2)(2X-5)=(2X)(3X-2)-29 ?
The answer to 3(X+2)(2X-5)=(2X)(3X-2)-29 is X=1
Solve for X: 3(X+2)(2X-5)=(2X)(3X-2)-29
The solution is X=1