What are the solutions to the equation 0=32t-16t^2 ?

The solutions to the equation 0=32t-16t^2 are t=0,t=2

Find the zeros of 0=32t-16t^2

The zeros of 0=32t-16t^2 are t=0,t=2

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0 = 32 t - 16 t^{2}

t = 0, t = 2

Solution steps

0 = 32 t - 16 t^{2}

Switch sides

32 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 32 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

3 2^{2} - 4 (- 16) \cdot 0 = 32

t_{1, 2} = \frac{- 32 \pm 32}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 32 + 32}{2 ( - 16 )}, t_{2} = \frac{- 32 - 32}{2 ( - 16 )}

t = \frac{- 32 + 32}{2 ( - 16 )} : 0

t = \frac{- 32 - 32}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

t = 0, t = 2

4 c i s (- \frac{2 π}{3})

a^{2} - 12 a + 20

(x + 2) (x - 3) > 0

x^{2} - 1 = 0

1521

What are the solutions to the equation 0=32t-16t^2 ?
The solutions to the equation 0=32t-16t^2 are t=0,t=2
Find the zeros of 0=32t-16t^2
The zeros of 0=32t-16t^2 are t=0,t=2