What is the answer to solvefor a,-Ba+9=Q^2a ?

The answer to solvefor a,-Ba+9=Q^2a is a= 9/(B+Q^2);\quad B\ne-Q^2

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solvefor a,-Ba+9=Q^2a

solve for

a, - B a + 9 = Q^{2} a

a = \frac{9}{B + Q ^{2}}; B \neq = - Q^{2}

Solution steps

- B a + 9 = Q^{2} a

Move

9

to the right side

- B a = Q^{2} a - 9

Move

Q^{2} a

to the left side

- B a - Q^{2} a = - 9

Factor

- B a - Q^{2} a : - a (B + Q^{2})

- a (B + Q^{2}) = - 9

Divide both sides by

- (B + Q^{2}); B \neq = - Q^{2}

a = \frac{9}{B + Q ^{2}}; B \neq = - Q^{2}

x, 2 x + 9 y = 36

x, 5 x - 8 y = - 29

4 (x - 2) - 5 (2 - 3 x) = 4 (2 x - 6)

2 x + 7 = 19

x + \frac{3 x - 9}{5} = 4 - \frac{5 x - 12}{3}

What is the answer to solvefor a,-Ba+9=Q^2a ?
The answer to solvefor a,-Ba+9=Q^2a is a= 9/(B+Q^2);\quad B\ne-Q^2