What are the solutions to the equation solvefor x,x^2+y^{24}=1 ?

The solutions to the equation solvefor x,x^2+y^{24}=1 are x=sqrt(1-y^{24)},x=-sqrt(1-y^{24)}

Find the zeros of solvefor x,x^2+y^{24}=1

The zeros of solvefor x,x^2+y^{24}=1 are x=sqrt(1-y^{24)},x=-sqrt(1-y^{24)}

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solve for

x, x^{2} + y^{24} = 1

x = 1 - y^{24}, x = - 1 - y^{24}

Solution steps

x^{2} + y^{24} = 1

Move

y^{24}

to the right side

x^{2} = 1 - y^{24}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1 - y^{24}, x = - 1 - y^{24}

- 4 n - 1 = 2 n - 25

x = 9 x

5 b - 4 = 10

y, x = 1 - 4 y

y, x = 1 - 2 y

What are the solutions to the equation solvefor x,x^2+y^{24}=1 ?
The solutions to the equation solvefor x,x^2+y^{24}=1 are x=sqrt(1-y^{24)},x=-sqrt(1-y^{24)}
Find the zeros of solvefor x,x^2+y^{24}=1
The zeros of solvefor x,x^2+y^{24}=1 are x=sqrt(1-y^{24)},x=-sqrt(1-y^{24)}