What is the answer to solvefor h,A= 1/2 (b^1+b^2)h ?

The answer to solvefor h,A= 1/2 (b^1+b^2)h is h=(2A)/(b+b^2);\quad b\ne 0,b\ne-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor h,A= 1/2 (b^1+b^2)h

solve for

h, A = \frac{1}{2} (b^{1} + b^{2}) h

h = \frac{2 A}{b + b ^{2}}; b \neq = 0, b \neq = - 1

Solution steps

A = \frac{1}{2} (b^{1} + b^{2}) h

Switch sides

\frac{1}{2} (b^{1} + b^{2}) h = A

Simplify

\frac{1}{2} (b^{1} + b^{2}) : \frac{1}{2} (b + b^{2})

\frac{1}{2} (b + b^{2}) h = A

Multiply both sides by

2

h (b + b^{2}) = 2 A

Divide both sides by

b + b^{2}; b \neq = 0, b \neq = - 1

h = \frac{2 A}{b + b ^{2}}; b \neq = 0, b \neq = - 1

lo g_{10} (3) (81) = 4

x, 3 x + y - 8 = 0

4 (x + 4) = 2 (x + 2)

3 x + 1 = x - 1

x, 3 x - 4 y = - 9

What is the answer to solvefor h,A= 1/2 (b^1+b^2)h ?
The answer to solvefor h,A= 1/2 (b^1+b^2)h is h=(2A)/(b+b^2);\quad b\ne 0,b\ne-1