What are the solutions to the equation (5x+1)^2=6 ?

The solutions to the equation (5x+1)^2=6 are x=(sqrt(6)-1)/5 ,x=(-sqrt(6)-1)/5

Find the zeros of (5x+1)^2=6

The zeros of (5x+1)^2=6 are x=(sqrt(6)-1)/5 ,x=(-sqrt(6)-1)/5

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(5 x + 1)^{2} = 6

x = \frac{6 - 1}{5}, x = \frac{- 6 - 1}{5}

Decimal Notation

x = 0.28989 \dots, x = - 0.68989 \dots

Solution steps

(5 x + 1)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 1 = 6 : x = \frac{6 - 1}{5}

Solve

5 x + 1 = - 6 : x = \frac{- 6 - 1}{5}

The solutions to the quadratic equation are:

x = \frac{6 - 1}{5}, x = \frac{- 6 - 1}{5}

\frac{0}{- 8}

\frac{5 x}{2} - x = \frac{x}{10} - \frac{14}{5}

\frac{7}{\frac{7}{6} + 5}

- 155 + 15 x = 45 + 7 x

\frac{4 !}{( 4 - 2 ) ! 2 !}

What are the solutions to the equation (5x+1)^2=6 ?
The solutions to the equation (5x+1)^2=6 are x=(sqrt(6)-1)/5 ,x=(-sqrt(6)-1)/5
Find the zeros of (5x+1)^2=6
The zeros of (5x+1)^2=6 are x=(sqrt(6)-1)/5 ,x=(-sqrt(6)-1)/5