What is the answer to solvefor x,[(x-3)] 2/16+[(y-1)] 2/25 =1 ?

The answer to solvefor x,[(x-3)] 2/16+[(y-1)] 2/25 =1 is x= 291/25-16/25 y

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solvefor x,[(x-3)] 2/16+[(y-1)] 2/25 =1

solve for

x, [(x - 3)] \frac{2}{16} + [(y - 1)] \frac{2}{25} = 1

x = \frac{291}{25} - \frac{16}{25} y

Solution steps

[(x - 3)] \frac{2}{16} + [(y - 1)] \frac{2}{25} = 1

Move

[(y - 1)] \frac{2}{25}

to the right side

[(x - 3)] \frac{2}{16} = \frac{27}{25} - \frac{2}{25} y

Expand

((x - 3)) \frac{2}{16} : \frac{x}{8} - \frac{3}{8}

\frac{x}{8} - \frac{3}{8} = \frac{27}{25} - \frac{2}{25} y

Multiply both sides by

8

x - 3 = \frac{216}{25} - \frac{16}{25} y

Move

3

to the right side

x = \frac{291}{25} - \frac{16}{25} y

x, 2 x - 2 y = - 6

x, 2 x - 2 y = - 2

x, 3 x - y = 5 y

\frac{3}{4} = 6

9 x = 180

What is the answer to solvefor x,[(x-3)] 2/16+[(y-1)] 2/25 =1 ?
The answer to solvefor x,[(x-3)] 2/16+[(y-1)] 2/25 =1 is x= 291/25-16/25 y