What is the answer to solvefor x,(3^{y-1})/5 =2x ?

The answer to solvefor x,(3^{y-1})/5 =2x is x=(3^{y-1})/(10)

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solvefor x,(3^{y-1})/5 =2x

solve for

x, \frac{3 ^{y - 1}}{5} = 2 x

x = \frac{3 ^{y - 1}}{10}

Solution steps

\frac{3 ^{y - 1}}{5} = 2 x

Switch sides

2 x = \frac{3 ^{y - 1}}{5}

Divide both sides by

2

x = \frac{3 ^{y - 1}}{10}

\frac{m}{- 8} = - 2.5

\frac{x + 9}{5} = \frac{x - 7}{10}

y, x + 4 y = 4

y, x + 4 y = 3

y, 2 x - 6 y = 12

What is the answer to solvefor x,(3^{y-1})/5 =2x ?
The answer to solvefor x,(3^{y-1})/5 =2x is x=(3^{y-1})/(10)