What is the answer to solvefor x, x/(1+y)-z=x ?

The answer to solvefor x, x/(1+y)-z=x is x=-(z+yz)/y ;\quad y\ne-1,y\ne 0

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solvefor x, x/(1+y)-z=x

solve for

x, \frac{x}{1 + y} - z = x

x = - \frac{z + yz}{y}; y \neq = - 1, y \neq = 0

Solution steps

\frac{x}{1 + y} - z = x

Move

z

to the right side

\frac{x}{1 + y} = x + z

Multiply both sides by

1 + y

x = x (1 + y) + z (1 + y); y \neq = - 1

Expand

x (1 + y) : x + x y

x = x + x y + z (1 + y)

Expand

z (1 + y) : z + yz

x = x + x y + z + yz; y \neq = - 1

Subtract

x + x y

from both sides

x - (x + x y) = x + x y + z + yz - (x + x y); y \neq = - 1

Simplify

- x y = z + yz; y \neq = - 1

Divide both sides by

- y; y \neq = - 1, y \neq = 0

x = - \frac{z + yz}{y}; y \neq = - 1, y \neq = 0

3 a - 1 = 14 - 6

- 117 = - 5 (8 x - 8) + 3

3 m + 4 = - 11

y = \frac{1}{2} - 3

- \frac{3}{8} = \frac{3}{4} a + \frac{1}{2}

What is the answer to solvefor x, x/(1+y)-z=x ?
The answer to solvefor x, x/(1+y)-z=x is x=-(z+yz)/y ;\quad y\ne-1,y\ne 0