What is the answer to solvefor x,y=in(x+3) ?

The answer to solvefor x,y=in(x+3) is x=-(iy)/n-3;\quad n\ne 0

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solvefor x,y=in(x+3)

solve for

x, y = in (x + 3)

x = - \frac{i y}{n} - 3; n \neq = 0

Solution steps

y = in (x + 3)

Switch sides

in (x + 3) = y

Divide both sides by

in; n \neq = 0

x + 3 = - \frac{i y}{n}; n \neq = 0

Move

3

to the right side

x = - \frac{i y}{n} - 3; n \neq = 0

2 (4 x) + 30 = 46

x, 2 y + 7 x = - 5

8 c + 29 c - 22 c + 14 c - 4 = - 33

b, - 15 d + 21 + 5 b = - 19

- 8 (x + 2) = 9

What is the answer to solvefor x,y=in(x+3) ?
The answer to solvefor x,y=in(x+3) is x=-(iy)/n-3;\quad n\ne 0