What is the answer to log_{10}(2)(x+1)+log_{10}(2)(x-1)=3 ?

The answer to log_{10}(2)(x+1)+log_{10}(2)(x-1)=3 is x= 3/(2log_{10)(2)}

Solve for x: log_{10}(2)(x+1)+log_{10}(2)(x-1)=3

The solution is x= 3/(2log_{10)(2)}

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lo g_{10} (2) (x + 1) + lo g_{10} (2) (x - 1) = 3

x = \frac{3}{2 lo g _{10} ( 2 )}

Decimal Notation

x = 4.98289 \dots

Solution steps

lo g_{10} (2) (x + 1) + lo g_{10} (2) (x - 1) = 3

Expand

lo g_{10} (2) (x + 1) + lo g_{10} (2) (x - 1) : 2 lo g_{10} (2) x

2 lo g_{10} (2) x = 3

Divide both sides by

2 lo g_{10} (2)

x = \frac{3}{2 lo g _{10} ( 2 )}

- 5 + x = 13

x, (y + 3) 225 - (x - 3) 236 = 1

b, b + d = 8

lo g_{\frac{1}{3}} (81) = x

85 = (73 - x) + (67 - x) + x + 18

What is the answer to log_{10}(2)(x+1)+log_{10}(2)(x-1)=3 ?
The answer to log_{10}(2)(x+1)+log_{10}(2)(x-1)=3 is x= 3/(2log_{10)(2)}
Solve for x: log_{10}(2)(x+1)+log_{10}(2)(x-1)=3
The solution is x= 3/(2log_{10)(2)}