What is the answer to 3x^2+(2-ab)x=3(x-b)^2 ?

The answer to 3x^2+(2-ab)x=3(x-b)^2 is x=(3b^2}{-ab+6b+2};\quad a\ne-\frac{-6b-2)/b

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3x^2+(2-ab)x=3(x-b)^2

3 x^{2} + (2 - ab) x = 3 (x - b)^{2}

x = \frac{3 b ^{2}}{- ab + 6 b + 2}; a \neq = - \frac{- 6 b - 2}{b}

Solution steps

3 x^{2} + (2 - ab) x = 3 (x - b)^{2}

Expand

3 x^{2} + (2 - ab) x : 3 x^{2} + 2 x - ab x

Expand

3 (x - b)^{2} : 3 x^{2} - 6 b x + 3 b^{2}

3 x^{2} + 2 x - ab x = 3 x^{2} - 6 b x + 3 b^{2}

Subtract

3 x^{2} - 6 b x

from both sides

3 x^{2} + 2 x - ab x - (3 x^{2} - 6 b x) = 3 x^{2} - 6 b x + 3 b^{2} - (3 x^{2} - 6 b x)

Simplify

- ab x + 6 b x + 2 x = 3 b^{2}

Factor

- ab x + 6 b x + 2 x : x (- ab + 6 b + 2)

x (- ab + 6 b + 2) = 3 b^{2}

Divide both sides by

- ab + 6 b + 2; a \neq = - \frac{- 6 b - 2}{b}

x = \frac{3 b ^{2}}{- ab + 6 b + 2}; a \neq = - \frac{- 6 b - 2}{b}

x + 7 = 4^{3}

6 (2 x + 2) = - 24

lo g_{9} (1) = 3 x - 18

x, y - 1 = - 3 (x + 2)

g, f = \frac{g}{h}

What is the answer to 3x^2+(2-ab)x=3(x-b)^2 ?
The answer to 3x^2+(2-ab)x=3(x-b)^2 is x=(3b^2}{-ab+6b+2};\quad a\ne-\frac{-6b-2)/b