What is the answer to 1/3 (6x-5)-x= 1/3-2(x+1) ?

The answer to 1/3 (6x-5)-x= 1/3-2(x+1) is x=0

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1/3 (6x-5)-x= 1/3-2(x+1)

\frac{1}{3} (6 x - 5) - x = \frac{1}{3} - 2 (x + 1)

x = 0

Solution steps

\frac{1}{3} (6 x - 5) - x = \frac{1}{3} - 2 (x + 1)

Expand

\frac{1}{3} (6 x - 5) - x : x - \frac{5}{3}

Expand

\frac{1}{3} - 2 (x + 1) : - 2 x - \frac{5}{3}

x - \frac{5}{3} = - 2 x - \frac{5}{3}

Move

\frac{5}{3}

to the right side

x = - 2 x

Move

2 x

to the left side

3 x = 0

Divide both sides by

3

x = 0

\frac{1}{2} (x + \frac{1}{3}) + \frac{1}{4} (\frac{2}{3} x - \frac{1}{6}) = x

y = lo g_{10} (100)

y, 3 x - y = 12

y = 1 - (- 1)^{2}

5 (1 - 2 x) + 3 (2 - x) = - 41

What is the answer to 1/3 (6x-5)-x= 1/3-2(x+1) ?
The answer to 1/3 (6x-5)-x= 1/3-2(x+1) is x=0
Solve for x: 1/3 (6x-5)-x= 1/3-2(x+1)
The solution is x=0