What are the solutions to the equation 8x^2-19x-15=0 ?

The solutions to the equation 8x^2-19x-15=0 are x=3,x=-5/8

Find the zeros of 8x^2-19x-15=0

The zeros of 8x^2-19x-15=0 are x=3,x=-5/8

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8 x^{2} - 19 x - 15 = 0

x = 3, x = - \frac{5}{8}

Decimal Notation

x = 3, x = - 0.625

Solution steps

8 x^{2} - 19 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

(- 19)^{2} - 4 \cdot 8 (- 15) = 29

x_{1, 2} = \frac{- ( - 19 ) \pm 29}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 29}{2 \cdot 8}, x_{2} = \frac{- ( - 19 ) - 29}{2 \cdot 8}

x = \frac{- ( - 19 ) + 29}{2 \cdot 8} : 3

x = \frac{- ( - 19 ) - 29}{2 \cdot 8} : - \frac{5}{8}

The solutions to the quadratic equation are:

x = 3, x = - \frac{5}{8}

\frac{3 - 2}{1 + 2}

\frac{1}{2} x + \frac{1}{3} = \frac{5}{6}

\frac{x - 2}{4} - \frac{x + 5}{6} = \frac{5 x - 2}{9}

(\frac{- 8 x ^{3}}{y ^{- 6}})^{\frac{2}{3}}

(x - 5)^{2} = 1

What are the solutions to the equation 8x^2-19x-15=0 ?
The solutions to the equation 8x^2-19x-15=0 are x=3,x=-5/8
Find the zeros of 8x^2-19x-15=0
The zeros of 8x^2-19x-15=0 are x=3,x=-5/8