What is the answer to (x-2)/3+(x+3)/4 = 7/12 ?

The answer to (x-2)/3+(x+3)/4 = 7/12 is x= 6/7

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(x-2)/3+(x+3)/4 = 7/12

\frac{x - 2}{3} + \frac{x + 3}{4} = \frac{7}{12}

x = \frac{6}{7}

Decimal Notation

x = 0.85714 \dots

Solution steps

\frac{x - 2}{3} + \frac{x + 3}{4} = \frac{7}{12}

Multiply by LCM

4 (x - 2) + 3 (x + 3) = 7

Expand

4 (x - 2) + 3 (x + 3) : 7 x + 1

7 x + 1 = 7

Move

1

to the right side

7 x = 6

Divide both sides by

7

x = \frac{6}{7}

b, m = \frac{b}{f}

- 5 (x + 9) = - 5

x, 4 x + y = 25

3 (x + 8) = 20

5 (3 x - 2) - 7 (x - 1) = 12

What is the answer to (x-2)/3+(x+3)/4 = 7/12 ?
The answer to (x-2)/3+(x+3)/4 = 7/12 is x= 6/7
Solve for x: (x-2)/3+(x+3)/4 = 7/12
The solution is x= 6/7