What are the solutions to the equation u^2-29u+100=0 ?

The solutions to the equation u^2-29u+100=0 are u=25,u=4

Find the zeros of u^2-29u+100=0

The zeros of u^2-29u+100=0 are u=25,u=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} - 29 u + 100 = 0

u = 25, u = 4

Solution steps

u^{2} - 29 u + 100 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

(- 29)^{2} - 4 \cdot 1 \cdot 100 = 21

u_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 1}, u_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 1}

u = \frac{- ( - 29 ) + 21}{2 \cdot 1} : 25

u = \frac{- ( - 29 ) - 21}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

u = 25, u = 4

3 x^{2} = 7 x

n + 10 > 15 or 4 n - 5 < - 1

2 x - 3 = 6

8 x - 7 = 6

x^{2} + 5 ∣ x ∣ - 6 = 0

What are the solutions to the equation u^2-29u+100=0 ?
The solutions to the equation u^2-29u+100=0 are u=25,u=4
Find the zeros of u^2-29u+100=0
The zeros of u^2-29u+100=0 are u=25,u=4