What is the answer to ((2-2(x-3)))/2-((x+4))/4 =3 ?

The answer to ((2-2(x-3)))/2-((x+4))/4 =3 is x=0

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((2-2(x-3)))/2-((x+4))/4 =3

\frac{( 2 - 2 ( x - 3 ) )}{2} - \frac{( x + 4 )}{4} = 3

x = 0

Solution steps

\frac{( 2 - 2 ( x - 3 ) )}{2} - \frac{( x + 4 )}{4} = 3

\frac{2 - 2 ( x - 3 )}{2} - \frac{x + 4}{4} = 3

Multiply by LCM

4 (- x + 4) - (x + 4) = 12

Expand

4 (- x + 4) - (x + 4) : - 5 x + 12

- 5 x + 12 = 12

Move

12

to the right side

- 5 x = 0

Divide both sides by

- 5

x = 0

\frac{B}{D - g} = n

2 x + 4 + 5 x = 18

3 (v - 6) - 8 = - 2

3 (b + 1) - 5 = 3 b - 2

\frac{- 2 x + 1}{2} + 6 = \frac{3 x}{2} - 10

What is the answer to ((2-2(x-3)))/2-((x+4))/4 =3 ?
The answer to ((2-2(x-3)))/2-((x+4))/4 =3 is x=0
Solve for x: ((2-2(x-3)))/2-((x+4))/4 =3
The solution is x=0