What is factor 100x^2+20x+1 ?

The solution to factor 100x^2+20x+1 is (10x+1)^2

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factor 100x^2+20x+1

factor

100 x^{2} + 20 x + 1

(10 x + 1)^{2}

Solution steps

100 x^{2} + 20 x + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

100 x^{2} = (10 x)^{2}

1 = 1^{2}

20 x = 2 \cdot 10 x \cdot 1

= (10 x)^{2} + 2 \cdot 10 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(10 x)^{2} + 2 \cdot 10 x \cdot 1 + 1^{2} = (10 x + 1)^{2}

= (10 x + 1)^{2}

lo g_{9} (2 x - 1) < 0.5

2 x - 1 = 0

\frac{4}{9} - \frac{1}{9}

(2 x y)^{2} (- 3 x^{2}) (4 y^{2})

(10 x y + 8 x^{2} z^{3}) - (6 y z^{2} + 3 yz)