What is the answer to log_{10}(4)(2x-64)+log_{10}(4)(x-1)=3 ?

The answer to log_{10}(4)(2x-64)+log_{10}(4)(x-1)=3 is x=(3+130log_{10}(2))/(6log_{10)(2)}

Solve for x: log_{10}(4)(2x-64)+log_{10}(4)(x-1)=3

The solution is x=(3+130log_{10}(2))/(6log_{10)(2)}

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lo g_{10} (4) (2 x - 64) + lo g_{10} (4) (x - 1) = 3

x = \frac{3 + 130 lo g _{10} ( 2 )}{6 lo g _{10} ( 2 )}

Decimal Notation

x = 23.32763 \dots

Solution steps

lo g_{10} (4) (2 x - 64) + lo g_{10} (4) (x - 1) = 3

Expand

lo g_{10} (4) (2 x - 64) + lo g_{10} (4) (x - 1) : 3 lo g_{10} (4) x - 65 lo g_{10} (4)

3 lo g_{10} (4) x - 65 lo g_{10} (4) = 3

Move

65 lo g_{10} (4)

to the right side

3 lo g_{10} (4) x = 3 + 130 lo g_{10} (2)

Divide both sides by

3 lo g_{10} (4)

x = \frac{3 + 130 lo g _{10} ( 2 )}{6 lo g _{10} ( 2 )}

a = \frac{x - b ^{2}}{2 c}

2098849 = \frac{( π ^{2} \cdot 210 \cdot 1 0 ^{6} \cdot x )}{( 9646 ) ^{2}}

y = (- 1 + 1)^{2}

x = - 10 i ((3.5 - 6.06217 i) - (3.29689 - 6.0563 i))

g (- 2) = (\frac{1}{4})^{- 2}

What is the answer to log_{10}(4)(2x-64)+log_{10}(4)(x-1)=3 ?
The answer to log_{10}(4)(2x-64)+log_{10}(4)(x-1)=3 is x=(3+130log_{10}(2))/(6log_{10)(2)}
Solve for x: log_{10}(4)(2x-64)+log_{10}(4)(x-1)=3
The solution is x=(3+130log_{10}(2))/(6log_{10)(2)}