What is the answer to (x-4)^2=20+(x+5)^2 ?

The answer to (x-4)^2=20+(x+5)^2 is x=-29/18

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(x-4)^2=20+(x+5)^2

(x - 4)^{2} = 20 + (x + 5)^{2}

x = - \frac{29}{18}

Decimal Notation

x = - 1.61111 \dots

Solution steps

(x - 4)^{2} = 20 + (x + 5)^{2}

Expand

(x - 4)^{2} : x^{2} - 8 x + 16

Expand

20 + (x + 5)^{2} : x^{2} + 10 x + 45

x^{2} - 8 x + 16 = x^{2} + 10 x + 45

Move

16

to the right side

x^{2} - 8 x = x^{2} + 10 x + 29

Subtract

x^{2} + 10 x

from both sides

x^{2} - 8 x - (x^{2} + 10 x) = x^{2} + 10 x + 29 - (x^{2} + 10 x)

Simplify

- 18 x = 29

Divide both sides by

- 18

x = - \frac{29}{18}

x, 2 x + 3 y + z = 0

x - 6 = - 36

x, 4 x - 3 y = 16

24 = - 3 x

x + \frac{( x + 12 )}{3} = \frac{32}{5}

What is the answer to (x-4)^2=20+(x+5)^2 ?
The answer to (x-4)^2=20+(x+5)^2 is x=-29/18
Solve for x: (x-4)^2=20+(x+5)^2
The solution is x=-29/18