What is the answer to (x-3)^2-x(x-5)=(x+4)(x-3)-(x+2)(x+1)+26 ?

The answer to (x-3)^2-x(x-5)=(x+4)(x-3)-(x+2)(x+1)+26 is x=3

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(x-3)^2-x(x-5)=(x+4)(x-3)-(x+2)(x+1)+26

(x - 3)^{2} - x (x - 5) = (x + 4) (x - 3) - (x + 2) (x + 1) + 26

x = 3

Solution steps

(x - 3)^{2} - x (x - 5) = (x + 4) (x - 3) - (x + 2) (x + 1) + 26

Expand

(x - 3)^{2} - x (x - 5) : - x + 9

Expand

(x + 4) (x - 3) - (x + 2) (x + 1) + 26 : - 2 x + 12

- x + 9 = - 2 x + 12

Move

9

to the right side

- x = - 2 x + 3

Move

2 x

to the left side

x = 3

2 (x + 3) + x = 6 (1 - \frac{1}{3} x)

8 m - 5 = 3 m - 20

\frac{x}{- 7} = - 9

x - 2 = 2 x + 4

- 8 a + 11 = - 21

What is the answer to (x-3)^2-x(x-5)=(x+4)(x-3)-(x+2)(x+1)+26 ?
The answer to (x-3)^2-x(x-5)=(x+4)(x-3)-(x+2)(x+1)+26 is x=3
Solve for x: (x-3)^2-x(x-5)=(x+4)(x-3)-(x+2)(x+1)+26
The solution is x=3