What is the answer to solvefor x,2x+3y+4z=20 ?

The answer to solvefor x,2x+3y+4z=20 is x=(20-3y-4z)/2

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solvefor x,2x+3y+4z=20

solve for

x, 2 x + 3 y + 4 z = 20

x = \frac{20 - 3 y - 4 z}{2}

Solution steps

2 x + 3 y + 4 z = 20

Move

3 y

to the right side

2 x + 4 z = 20 - 3 y

Move

4 z

to the right side

2 x = 20 - 3 y - 4 z

Divide both sides by

2

x = \frac{20 - 3 y - 4 z}{2}

13 x + 7 (- 3 x - 1) = - 63

x, 2 x - 4 y + 7 = 0

(x + 12) + (4 x - 7) = 180

a, 2 = \frac{1}{b} \cdot 1 + \frac{a}{b}

y, 3 x + 9 = 2 x + 4 y

What is the answer to solvefor x,2x+3y+4z=20 ?
The answer to solvefor x,2x+3y+4z=20 is x=(20-3y-4z)/2