What is the answer to solvefor f,f(4+h)=1+4(4+h)-(4+h)^2 ?

The answer to solvefor f,f(4+h)=1+4(4+h)-(4+h)^2 is f=(-h^2-4h+1)/(4+h);\quad h\ne-4

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solvefor f,f(4+h)=1+4(4+h)-(4+h)^2

solve for

f, f (4 + h) = 1 + 4 (4 + h) - (4 + h)^{2}

f = \frac{- h ^{2} - 4 h + 1}{4 + h}; h \neq = - 4

Solution steps

f (4 + h) = 1 + 4 (4 + h) - (4 + h)^{2}

Divide both sides by

4 + h; h \neq = - 4

f = \frac{- h ^{2} - 4 h + 1}{4 + h}; h \neq = - 4

\frac{93.75 - x}{750} + \frac{x}{375} = 0.15

4 x - 3 (x - 2) = 21

\frac{2 m - 1}{2} + \frac{m}{3} = m - 3

- 9.1 = 2.1 + \frac{y}{7}

- 12 x = 48

What is the answer to solvefor f,f(4+h)=1+4(4+h)-(4+h)^2 ?
The answer to solvefor f,f(4+h)=1+4(4+h)-(4+h)^2 is f=(-h^2-4h+1)/(4+h);\quad h\ne-4