What is the answer to |(x+1)/2-(x+2)/3+(x+3)/5 |=0 ?

The answer to |(x+1)/2-(x+2)/3+(x+3)/5 |=0 is x=-13/11

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|(x+1)/2-(x+2)/3+(x+3)/5 |=0

\frac{x + 1}{2} - \frac{x + 2}{3} + \frac{x + 3}{5} = 0

x = - \frac{13}{11}

Decimal Notation

x = - 1.18181 \dots

Solution steps

\frac{x + 1}{2} - \frac{x + 2}{3} + \frac{x + 3}{5} = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

\frac{x + 1}{2} - \frac{x + 2}{3} + \frac{x + 3}{5} = 0

\frac{x + 1}{2} - \frac{x + 2}{3} + \frac{x + 3}{5} = 0 : x = - \frac{13}{11}

x = - \frac{13}{11}

\frac{4}{5} - 3

p^{2} - 4 k^{2}

x^{2} + 2 x - 8

lo g_{2} (3) + lo g_{2} (5)

What is the answer to |(x+1)/2-(x+2)/3+(x+3)/5 |=0 ?
The answer to |(x+1)/2-(x+2)/3+(x+3)/5 |=0 is x=-13/11
Solve for x: |(x+1)/2-(x+2)/3+(x+3)/5 |=0
The solution is x=-13/11