What is the answer to ((y+1))/2+((y-1))/3 =1 ?

The answer to ((y+1))/2+((y-1))/3 =1 is y=1

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((y+1))/2+((y-1))/3 =1

\frac{( y + 1 )}{2} + \frac{( y - 1 )}{3} = 1

y = 1

Solution steps

\frac{( y + 1 )}{2} + \frac{( y - 1 )}{3} = 1

\frac{y + 1}{2} + \frac{y - 1}{3} = 1

Multiply by LCM

3 (y + 1) + 2 (y - 1) = 6

Expand

3 (y + 1) + 2 (y - 1) : 5 y + 1

5 y + 1 = 6

Move

1

to the right side

5 y = 5

Divide both sides by

5

y = 1

4 h - 6 = 12

7 x - 4 = 171

5 x + 5 = 3 (5 x - 4) - 10 x

5.6 b = 30

x, y + 3 x = 6

What is the answer to ((y+1))/2+((y-1))/3 =1 ?
The answer to ((y+1))/2+((y-1))/3 =1 is y=1
Solve for y: ((y+1))/2+((y-1))/3 =1
The solution is y=1