What is the answer to (x-3)/4-(3x+3)/(10)=2x+1 ?

The answer to (x-3)/4-(3x+3)/(10)=2x+1 is x=-1

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(x-3)/4-(3x+3)/(10)=2x+1

\frac{x - 3}{4} - \frac{3 x + 3}{10} = 2 x + 1

x = - 1

Solution steps

\frac{x - 3}{4} - \frac{3 x + 3}{10} = 2 x + 1

Multiply by LCM

5 (x - 3) - 2 (3 x + 3) = 40 x + 20

Expand

5 (x - 3) - 2 (3 x + 3) : - x - 21

- x - 21 = 40 x + 20

Move

21

to the right side

- x = 40 x + 41

Move

40 x

to the left side

- 41 x = 41

Divide both sides by

- 41

x = - 1

x, \frac{x}{3} + \frac{y}{4} = \frac{7}{6}

E = 21 + 20 i + - 12 - 16 i

4 x - 15 = 215

b (n) = - 8 - 2 (n - 1)

s, s (k) = 4^{2 k - 2}

What is the answer to (x-3)/4-(3x+3)/(10)=2x+1 ?
The answer to (x-3)/4-(3x+3)/(10)=2x+1 is x=-1
Solve for x: (x-3)/4-(3x+3)/(10)=2x+1
The solution is x=-1