What is the answer to solvefor P,0.11P=P(2^{-x}) ?

The answer to solvefor P,0.11P=P(2^{-x}) is P=0

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solvefor P,0.11P=P(2^{-x})

solve for

P, 0.11 P = P (2^{- x})

P = 0

Solution steps

0.11 P = P (2^{- x})

Multiply both sides by

100

11 P = 25 \cdot 2^{- x + 2} P

Move

25 \cdot 2^{- x + 2} P

to the left side

11 P - 25 \cdot 2^{- x + 2} P = 0

Factor

11 P - 25 \cdot 2^{- x + 2} P : P (11 - 25 \cdot 2^{2 - x})

P (11 - 25 \cdot 2^{2 - x}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

P = 0

- 15 + 3 (2 x + 12) = 5 (x + 8) - 25

- 4 g + 11 = 5

y, 5 x + 4 y = 0

6 x + 3 x = 18

x, - 6 x - 6 y = 0

What is the answer to solvefor P,0.11P=P(2^{-x}) ?
The answer to solvefor P,0.11P=P(2^{-x}) is P=0