What is the answer to (2x+1)/3-(x-3)/5+(3x+7)/(10)=0 ?

The answer to (2x+1)/3-(x-3)/5+(3x+7)/(10)=0 is x=-49/23

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(2x+1)/3-(x-3)/5+(3x+7)/(10)=0

\frac{2 x + 1}{3} - \frac{x - 3}{5} + \frac{3 x + 7}{10} = 0

x = - \frac{49}{23}

Solution steps

\frac{2 x + 1}{3} - \frac{x - 3}{5} + \frac{3 x + 7}{10} = 0

Multiply by LCM

10 (2 x + 1) - 6 (x - 3) + 3 (3 x + 7) = 0

Expand

10 (2 x + 1) - 6 (x - 3) + 3 (3 x + 7) : 23 x + 49

23 x + 49 = 0

Move

49

to the right side

23 x = - 49

Divide both sides by

23

x = - \frac{49}{23}

\frac{x}{2} + \frac{1}{3} = \frac{x}{4}

- 2 y = 1

- 4 = - 4

\frac{4 x - 5}{2} = \frac{7 x - 3}{9}

- 14 x - 1 = 6

What is the answer to (2x+1)/3-(x-3)/5+(3x+7)/(10)=0 ?
The answer to (2x+1)/3-(x-3)/5+(3x+7)/(10)=0 is x=-49/23
Solve for x: (2x+1)/3-(x-3)/5+(3x+7)/(10)=0
The solution is x=-49/23