What are the solutions to the equation x^2-8x=20 ?

The solutions to the equation x^2-8x=20 are x=10,x=-2

Find the zeros of x^2-8x=20

The zeros of x^2-8x=20 are x=10,x=-2

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x^{2} - 8 x = 20

x = 10, x = - 2

Solution steps

x^{2} - 8 x = 20

Move

20

to the left side

x^{2} - 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 1}

x = \frac{- ( - 8 ) + 12}{2 \cdot 1} : 10

x = \frac{- ( - 8 ) - 12}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 10, x = - 2

\frac{3 x + 5}{4} = \frac{x}{2}

\frac{3 !}{1 ! ( 3 - 1 ) !}

2 t^{2} - 8

(\frac{21}{2})^{2}

(a + b)^{4} - (a - b)^{4}

What are the solutions to the equation x^2-8x=20 ?
The solutions to the equation x^2-8x=20 are x=10,x=-2
Find the zeros of x^2-8x=20
The zeros of x^2-8x=20 are x=10,x=-2