What is the answer to (x+3)^2+3(x-3)(x+3)=(2x-5)(2x+5)-8 ?

The answer to (x+3)^2+3(x-3)(x+3)=(2x-5)(2x+5)-8 is x=-5/2

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(x+3)^2+3(x-3)(x+3)=(2x-5)(2x+5)-8

(x + 3)^{2} + 3 (x - 3) (x + 3) = (2 x - 5) (2 x + 5) - 8

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

(x + 3)^{2} + 3 (x - 3) (x + 3) = (2 x - 5) (2 x + 5) - 8

Expand

(x + 3)^{2} + 3 (x - 3) (x + 3) : 4 x^{2} + 6 x - 18

Expand

(2 x - 5) (2 x + 5) - 8 : 4 x^{2} - 33

4 x^{2} + 6 x - 18 = 4 x^{2} - 33

Move

18

to the right side

4 x^{2} + 6 x = 4 x^{2} - 15

Move

4 x^{2}

to the left side

6 x = - 15

Divide both sides by

6

x = - \frac{5}{2}

\frac{x - 4}{6} = \frac{x + 2}{7}

6^{2} = x

- 6 x = - 36

27866.2 = 24800 (1 + \frac{x}{100} \cdot \frac{9}{12})

2 (w + 2) + w = 3 (w - 1) + 6

What is the answer to (x+3)^2+3(x-3)(x+3)=(2x-5)(2x+5)-8 ?
The answer to (x+3)^2+3(x-3)(x+3)=(2x-5)(2x+5)-8 is x=-5/2
Solve for x: (x+3)^2+3(x-3)(x+3)=(2x-5)(2x+5)-8
The solution is x=-5/2