What is the answer to E=(5^4)^{10}+(7^2)^{10}-(5^8)^5-(7^5)^4 ?

The answer to E=(5^4)^{10}+(7^2)^{10}-(5^8)^5-(7^5)^4 is E=0

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E=(5^4)^{10}+(7^2)^{10}-(5^8)^5-(7^5)^4

E = (5^{4})^{10} + (7^{2})^{10} - (5^{8})^{5} - (7^{5})^{4}

E = 0

Solution steps

E = (5^{4})^{10} + (7^{2})^{10} - (5^{8})^{5} - (7^{5})^{4}

Simplify

(5^{4})^{10} + (7^{2})^{10} - (5^{8})^{5} - (7^{5})^{4} : 0

E = 0

- 17 - \frac{3}{4} x = - 1 - (1 - \frac{1}{4} x)

2 - 3 x - 5 = 5 - 8 x + x

512 x + 23 x = 37

6 x - 10 x - 11 = 8 x - 2 x + 29

x, y - 4 x = - 1

What is the answer to E=(5^4)^{10}+(7^2)^{10}-(5^8)^5-(7^5)^4 ?
The answer to E=(5^4)^{10}+(7^2)^{10}-(5^8)^5-(7^5)^4 is E=0
Solve for E: E=(5^4)^{10}+(7^2)^{10}-(5^8)^5-(7^5)^4
The solution is E=0