What is the answer to solvefor x,31x+42y+33z=2 ?

The answer to solvefor x,31x+42y+33z=2 is x=(2-42y-33z)/(31)

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solvefor x,31x+42y+33z=2

solve for

x, 31 x + 42 y + 33 z = 2

x = \frac{2 - 42 y - 33 z}{31}

Solution steps

31 x + 42 y + 33 z = 2

Move

42 y

to the right side

31 x + 33 z = 2 - 42 y

Move

33 z

to the right side

31 x = 2 - 42 y - 33 z

Divide both sides by

31

x = \frac{2 - 42 y - 33 z}{31}

y = 4 (- 2) + 1

x, 3 x + y - 2 z = 1

x, - 5 x + 9 y = - 18

3 x = 4 + 2 x

t, u = \frac{3 t}{4} + 2

What is the answer to solvefor x,31x+42y+33z=2 ?
The answer to solvefor x,31x+42y+33z=2 is x=(2-42y-33z)/(31)