What is the answer to 3(-2)^2-3(-2)+k=4 ?

The answer to 3(-2)^2-3(-2)+k=4 is k=-14

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3(-2)^2-3(-2)+k=4

3 (- 2)^{2} - 3 (- 2) + k = 4

k = - 14

Solution steps

3 (- 2)^{2} - 3 (- 2) + k = 4

Simplify

3 (- 2)^{2} - 3 (- 2) + k : k + 18

k + 18 = 4

Move

18

to the right side

k = - 14

- 14 = 4 x - 2

36 = 2

x, 4 x + y + 2 = 0

2 (2 y - 5) + 2 y = 68

\frac{a - x}{b} + \frac{b}{a} = \frac{x - 2 a}{a}

What is the answer to 3(-2)^2-3(-2)+k=4 ?
The answer to 3(-2)^2-3(-2)+k=4 is k=-14
Solve for k: 3(-2)^2-3(-2)+k=4
The solution is k=-14