What are the solutions to the equation (x-2)(x+6)=9 ?

The solutions to the equation (x-2)(x+6)=9 are x=3,x=-7

Find the zeros of (x-2)(x+6)=9

The zeros of (x-2)(x+6)=9 are x=3,x=-7

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(x - 2) (x + 6) = 9

x = 3, x = - 7

Solution steps

(x - 2) (x + 6) = 9

Expand

(x - 2) (x + 6) : x^{2} + 4 x - 12

x^{2} + 4 x - 12 = 9

Move

9

to the left side

x^{2} + 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 10}{2 \cdot 1}

x = \frac{- 4 + 10}{2 \cdot 1} : 3

x = \frac{- 4 - 10}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

4 x - (6 x + 1) \leq 8 x + 2 (x - 3)

\frac{1}{4 ^{3}}

- - 72

x^{3} - 6 x^{2}

2 x^{2} - 4 x - 10

What are the solutions to the equation (x-2)(x+6)=9 ?
The solutions to the equation (x-2)(x+6)=9 are x=3,x=-7
Find the zeros of (x-2)(x+6)=9
The zeros of (x-2)(x+6)=9 are x=3,x=-7